 First, we need to find the smallest part of the dividend that
is greater than the divisor 110_{2}.
Since our divisor has three digits, we begin by examining the
first three digits of the dividend. 100_{2}
is less than 110_{2} so we need
to add another digit from our dividend.

110100001

 Next we try the first four digits of the dividend. Since 1000_{2}
is greater than 110_{2} we know
we can do our division.

110100001

 110_{2} divides 1000_{2}
one time, so we write a 1 as the first digit of our quotient,
copy the divisor below the dividend, and subtract using the
borrow method.

1
110100001
110
10

 Now we bring down the next digit of our dividend and write it
beside our remainder. Then we check to see if this new number
is greater than or equal to our divisor.

1
110100001
110
100

 100_{2} is less than 110_{2}
so we write a 0 in the quotient and add another digit to our reminder.

10
110100001
110
1001

 1001_{2} is greater than 110_{2}
so we write a 1 in the quotient and subtract 110_{2}
from 1001_{2}.

101
110100001
110
1001
110
11

 Note that we still have a remainder after considering all the
digits of the dividend. This means our answer will include a fraction.
To finish our problem we need to mark the radix point and append
a zero to the dividend.

101.
110100001.0
110
1001
110
11

 Now we bring down the extra zero and compare the remainder with
our divisor. Notice we ignore the radix point in our comparison.
110_{2} equals 110_{2}
so we write another 1 in the quotient and subtract. This completes
our division because we have no more digits in the dividend and
no remainder.

101.1
110100001.0
110
1001
110
110
110
0
